Evaporation factor = 2257/(2776-250.9) = 0.89 evaporation factor Boiler equivalent rate = 5000 x 0.89 = 4469 kg/Hr .
Get a QuoteP = 12.5 bar T = 35°C x = 0.85 From steam tables at 12.5 bar pressure h f = 806.7 kJ/kg h fg = 1977.4 kJ/kg h = h f + x(h fg) = 806.7 +0.85(1977.4) = 2487.49 kJ/kg h f1 = 4.18(T-0) = 4.18(35-0) = 146.3 kJ/kg Factor of evaporation f=(frac{h-h_{f1}}{2257} ) f=(frac{2487.49-146.3}{2257} ) f=1.04.
Get a QuoteTo be able to determine electrical power on alternating current (AC) systems you need to know the power factor of the electrical load. View More; Boiler Formulas - Johnston Boiler. Factor of Evaporation Water enters the boiler at 225°F. The boiler pressure is 100 psi and the boiler water temperature is 338°F. The latent heat is 881 Btu. View ...
Get a QuoteTo be able to determine electrical power on alternating current (AC) systems you need to know the power factor of the electrical load. View More; Boiler Formulas - Johnston Boiler. Factor of Evaporation Water enters the boiler at 225°F. The boiler pressure is 100 psi and the boiler water temperature is 338°F. The latent heat is 881 Btu. View ...
Get a QuoteEvaporation loss = 0.00085 x 10 000 x (100-85) = 127.5 gpm. Drift loss = 0.02% x 10 000 = 2 gpm. Blowdown = [127.5 (5-1) x 2]/(5-1) = 29.87 gpm. Cooling tower makeup water = 127.5
Get a QuoteA boiler generates 7.5 kg of steam per kg of coal burnt at a pressure of 11 bar from feed water having a temperature of 70ºC. The efficiency of the boiler is 75 % and factor of evaporation is 1.15 calculate
Get a QuoteThe factor of evaporation of a boiler is 1.1 and a steam rate of 0.79 KG/sec. What is the developd boiler horse power? A. 300 B. 200 C. 869 D. 250 5. The percent rating is water tube boiler is 200% factor of evaporation of 1.08 and heating surface area is 256 m². Find the rate of evaporation.
Get a QuoteThe factor of evaporation for all boilers is always greater than unity. B. The amount of water evaporated in kg per kg of fuel burnt is called equivalent evaporation from and at 100° C. C. The ratio of heat actually used in producing the steam to the heat liberated in the furnace is called boiler
Get a QuoteVarious Factors Affecting Evaporation 1. Temperature. The rate of evaporation is directly dependent on the temperature its exposed to. The more the temperature the more liquid its exposed to. The kinetic energy increases and the liquid gets converted to vapor instead. This increases the rate of evaporation.
Get a QuoteThe factor of evaporation for all boilers is always (A) Equal to unity (B) Less than unity (C) Greater than unity (D) None of these
Get a Quote2011-12-13 · STEAM Factor of Evaporation. The factor of evaporation for any given feed water temperature and boiler pressure is calculated by dividing the total heat above F. in one pound of steam at the given pressure minus the total heat in one pound of the feed water above F. by the latent heat of steam at F. which is 970.4 British Thermal Units.
Get a QuoteIn the table of " Factors of Evaporation " the factor corresponding to a steam temperature of 302° and a feed temperature of 158° (which are the numbers in the table nearest to the given ones) is 1.09. Now this engine requires an evaporation of 6 times 79 or 474 pounds of water per hour at a pressure of 50 pounds or an equivalent evaporation " from and at 212°" of 1.09 times 474 which is equal to 516.66
Get a QuoteThe fuel savings as can be seen from the figure can be substantial depending on the boiler operating time. As expected the longer the boiler stands-by the larger are the fuel savings. Thus a boiler operating for 12 hours firing typically for about one-third of a cycle has a fuel saving of 5.5% compared to 1.7% for 24 hours operation.
Get a QuoteFactor of evaporation in boiler definition dragon12 This will be 30 pounds multiplied by the factor of evaporation for 70 pounds gauge pressure and 100 degrees feed temperature or 1.1494. 30 × 1.1494 = 34.482 or approximately 34.5 pounds.
Get a QuoteThe factor of evaporation for all boilers is always. A. Equal to unity. B. Less than unity. C. Greater than unity. D. None of these. Answer: Option C . Join The Discussion. Comment * Related Questions on Steam Boilers Engines Nozzles and Turbines. The expansion of steam in
Get a QuoteNov 14 2018 · 18-1 in a steam boiler system what is the term used for replacing the water that has been lost by blowing down the boiler or through leaks in the system ... 26-1 the evaporation of 34.5 pounds of water per hour from and at a temperature of 212 degrees f is defined as ... The factor of evaporation . D. An evaporaton test. 16. 27-1 when a ...
Get a QuoteMar 17 2015 · Step 1: Determine Properties of Steam Produced Using the Steam Property Calculator properties are determined using Steam Pressure and the selected second parameter (Temperature Specific Enthalpy Specific Entropy or Quality). The Specific Enthalpy is then multiplied by the Mass Flow to get the Energy Flow: Pressure = 605.5 psig; Temperature = 701.7 °C
Get a QuoteThe percent rating of water tube boiler is 200 % factor of evaporation is 1.10 and heating surface is 400 ft 2. Determine the rate of evaporation in kg/hr. a) 1831 b) 1831 c) 1138 d) 1813 95 63.
Get a Quote(A) The factor of evaporation for all boilers is always greater than unity (B) The amount of water evaporated in kg per kg of fuel burnt is called equivalent evaporation from and at 100° C (C) The ratio of heat actually used in producing the steam to the heat liberated in the furnace is called boiler efficiency (D) None of the above
Get a QuoteP = 12.5 bar T = 35°C x = 0.85 From steam tables at 12.5 bar pressure h f = 806.7 kJ/kg h fg = 1977.4 kJ/kg h = h f + x(h fg) = 806.7 +0.85(1977.4) = 2487.49 kJ/kg h f1 = 4.18(T-0) = 4.18(35-0) = 146.3 kJ/kg Factor of evaporation f=(frac{h-h_{f1}}{2257} ) f=(frac{2487.49-146.3}{2257} ) f=1.04.
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